A unit vector perpendicular to A→=2i^+3j^+k^ and B→=i^−j^+k^ both is:
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a
114(4i^−j^−5k^)
b
142(4i^−j^−5k^)
c
114(i^−j^+k^)
d
142(2i^+3j^+k^)
answer is B.
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Detailed Solution
Let R→ is the vector perpendicular to A→ and B→ both suchThat R→=A→×B→R^=R→R=A→×B→|A→×B→|A→×B→=i ⏜ j ⏜ k ⏜ 2 3 1 1 -1 1 =i^(3+1)−j^(2−1)+k^(−2−3)=4i^−j^−5k^And |A→×B→|=(4)2+(−1)2+(−5)2=42Thus, R^=4i^−j^−5k^42