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Polarisation

Question

Unpolarised light of intensity 32 W/m2 passes through a polariser and analyser which are at an angle of 300 with respect to each other. The intensity of the light coming from analyser is

Moderate
Solution

 

I = \frac{{{I_0}}}{2}{\cos ^2}\theta \Rightarrow I = \frac{{32}}{2}{\cos ^2}{30^0}\
= \frac{{32}}{2} \times \frac{3}{4} = 12W/{m^2}\



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