First slide
Thermal expansion
Question

Upon heating, the length of the side of a cube changes by 2%. The volume of the cube changes by

Easy
Solution

% change in length \large \frac {\Delta l}{l}\times 100=2%
We have % change in volume
\large \frac {\Delta V}{V}\times 100=3\left ( \frac {\Delta l}{l}\times 100 \right )=3(2)=6%

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