First slide

Stress and strain

Question

The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through an angle of $30 °$ . Then angle of shear is

Easy

A

12°
B

0.12°
C

1.2°
D

0.012°

Solution

Angle of shear $ϕ = \frac{rθ}{L} = \frac{4 \times 10^{- 1}}{100} \times 30 ° = 0.12 °$

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