First slide

Projection Under uniform Acceleration

Question

At the upper most point of a projectile, its velocity and acceleration are at an angle of

Easy

A

$0^{\circ}$
B

45°
C

90°
D

180°

Solution

We know that at the upper-most point of a projectile the vertical component of the velocity becomes zero, while the horizontal component remains constant. And the acceleration due to gravity is always vertically downwards. Therefore at the upper-most point of a projectile, its velocity and acceleration are at an angle of 90°.

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