Using mass (M), length (L), time (T) and current (A) as fundamental quantities, what should be the dimension of permeability?
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a
M−1LT−2A
b
ML−2T−2A−1
c
MLT−2A−2
d
MLT−1A−1
answer is C.
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Detailed Solution
Speed of light in vacuum is given as c=1μoεo So, μo=1c2εo……(i)According coulomb force between two charges at rest, is given asF=14πεoq1q2r2 So, εn=14πq1q2Fr2……(ii)By equations (i) and (ii)μo=4πFr2c2q1q2By principle of homogeneityμo=4πFr2c2q1q2=MLT−2A−2