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Q.

Using mass (M), length (L), time (T) and current (A) as fundamental quantities, what should be the dimension of permeability?

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a

M−1LT−2A

b

ML−2T−2A−1

c

MLT−2A−2

d

MLT−1A−1

answer is C.

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Detailed Solution

Speed of light in vacuum is given as c=1μoεo So, μo=1c2εo……(i)According coulomb force between two charges at rest, is given asF=14πεoq1q2r2 So, εn=14πq1q2Fr2……(ii)By equations (i) and (ii)μo=4πFr2c2q1q2By principle of homogeneityμo=4πFr2c2q1q2=MLT−2A−2
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