Questions
Using mass (M), length (L), time (T), and electric current (A) as fundamental quantities, the dimensions of permittivity will be
a
MLT−1A−1
b
MLT−2A−2
c
M−1L−3T4A2
d
M2L−2T−2A
detailed solution
Correct option is C
By Coulomb's laws, F=14πε0×q1q2r2ε0=q1q24π×F×r2Taking dimensions,ε0=(AT)(AT)ML1T−2×L2=M−1L−3T4A2Talk to our academic expert!
Similar Questions
The quantities A and B are related by the relation A/B = m, where m is the linear mass density and A is the force, the dimensions of B will be
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