Using mass (M), length(L), time (T) and current (A) as fundamental quantities, the dimensional formula of permittivity is
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a
ML−2T2A
b
M−1L−3T4A2
c
MLT−2A
d
ML2T−1A2
answer is B.
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Detailed Solution
From Coulomb’s law, F = 14πεoq1q2r2⇒ εo = 14πq1q2Fr2 ∴ Dimensions of permittivity εo = Dimensions of q2Dimensions of F × dimensions of r2εo = A2T2MLT−2L2 = M−1L−3T4A2