First slide

Fluid statics

Question

A U-tube containing a liquid is accelerated horizontally with a constant acceleration a. If the separation between the two vertical limbs is l, then the difference in the heights of the liquid in the two arms is:

Moderate

A

zero
B

l
C

$\frac{la}{g}$
D

$\frac{\lg}{a}$

Solution

We know, tan $θ = \frac{a}{g}$
In the present problem, tan $θ = \frac{h}{l}$
So $\frac{h}{l} = \frac{a}{g} or h = \frac{al}{g}$
(where h is the difference in the heights in the two limbs)

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