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Q.

A U–tube contains some non–viscous liquid upto a depth h. The tube starts moving to the right parallel to its base with constant acceleration ‘a’. Find the height of liquid column in arm(1)

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a

h+2ab3g

b

h+ab2g

c

h+abg

d

h+3ab4g

answer is B.

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Detailed Solution

tanθ = ag h1−h2b = ag⇒ h1−h2 = abg−−−(1) Also,h1+h2+bA = h+h+bA ⇒ h1+h2 = 2h−−−−(2) Solving,h1 = h+ab2g

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A U–tube contains some non–viscous liquid upto a depth h. The tube starts moving to the right parallel to its base with constant acceleration ‘a’. Find the height of liquid column in arm(1)