ve and vp denotes the escape velocity from the earth and another planet having twice the radius and the same mean density as the earth. Then

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ve=vp

ve=vp/2

ve=2vp

ve=vp/4

answer is B.

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Detailed Solution

ve=2GMR=R83πGρIf mean density is constant then ve∝Rvevp=ReRp=12⇒ve=vp2

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