The V – I graph for a conductor at temperature T1 and T2 are as shown in figure. Then (T2– T1) is equal to [α = temperature coefficient of resistivity]
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a
2α
b
4α
c
8α
d
1α
answer is A.
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Detailed Solution
According to Ohm’s Law, V = R.I. It means that ‘R’ is the slope of V – I graph.∴ R1=tanθ and ∴ R2=R1 1+α T2−T1 ∴ cotθ = tanθ 1+α T2−T1 ⇒ α T2−T1=cotθtanθ−1 ⇒ T2−T1=1α . cos2θsin2θ = 1α cos600sin2300=2α
The V – I graph for a conductor at temperature T1 and T2 are as shown in figure. Then (T2– T1) is equal to [α = temperature coefficient of resistivity]