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Q.

V1andV2 are the stopping potentials for the incident radiations of  wave lengths λ1andλ2  respectively are incident on a metallic surface. λ1=3λ2 then

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a

V1>3V2

b

V2=3V1

c

V1>V23

d

V1

answer is D.

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Detailed Solution

hcλ1=w+eV1 hcλ2=w+eV2 λ1=3λ2 hc3λ2=w+eV1 w+eV2=3w+3eV1 3eV1=eV2−2w V1=V23−2w3e V1
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