A 100 V voltmeter of internal resistance 20 kΩ in series with a high resistance R is connected to a 110 V line. If the voltmeter reads 5 V the value of R is
210 kΩ
315 kΩ
420 kΩ
440 kΩ
Here i = 11020 × 103+R∵ V=iR ⇒ 5= 11020 × 103 +R × 20 × 103⇒ 105 +5R=22 × 105 ⇒ R=21 × 1055 =420 kΩ