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Questions  

A 100 V voltmeter of internal resistance 20  kΩ in series with a high resistance R is connected to a 110 V line. If the voltmeter reads 5 V the value of R is

a
210  kΩ
b
315  kΩ
c
420  kΩ
d
440  kΩ

detailed solution

Correct option is C

Here i  = 11020  × 103+R∵  V=iR ⇒  5= 11020 ×  103 +R ×   20 × 103⇒ 105 +5R=22  ×  105 ⇒ R=21 ×  1055 =420  kΩ

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