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The value of the acceleration due to gravity is $g_{1}$ at a height $h = \frac{R}{2}$ ( R= radius of the earth) from the surface of the earth. It is again equal to $g_{1}$ at a depth d below the surface of the earth. The ratio $(\frac{d}{R})$ equals

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Correct option is B

At height : g=GMR+h2=GMR+R22=49GMR2At depth : g=g1-dR=GMR3R-d∵g=GMR2∴49GMR2=GMR3R-d⇒dR=59

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The value of the acceleration due to gravity is g1 at a height h=R2 ( R= radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface of the earth. The ratio dR equals

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Ready to Test Your Skills?

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The value of the acceleration due to gravity is $g_{1}$ at a height $h = \frac{R}{2}$ ( R= radius of the earth) from the surface of the earth. It is again equal to $g_{1}$ at a depth d below the surface of the earth. The ratio $(\frac{d}{R})$ equals