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Q.

The value of the acceleration due to gravity is g1 at a height  h=R2 ( R= radius of the earth) from the surface of the earth. It is again equal to  g1 at a depth d below the surface of the earth. The ratio dR equals

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a

49

b

59

c

13

d

79

answer is B.

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Detailed Solution

At height  : g=GMR+h2=GMR+R22=49GMR2​At depth : g=g1-dR=GMR3R-d∵g=GMR2​​∴49GMR2=GMR3R-d​⇒dR=59
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