The value of (A→+B→)×(A→−B→) is
0
A2−B2
B→×A→
2(B→×A→)
(A→+B→)×(A→−B→)=A→×A→−A→×B→+B→×A→−B→×B→=0−A→×B→+B→×A→−0=B→×A→+B→×A→=2(B→×A→)