The value of the constant p such that the vectors 2i^−j^+k^,i^+2j^−3k^ and 3i^+pj^+5k^ are coplanar is:
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a
Zero
b
2
c
-4
d
-2
answer is C.
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Detailed Solution
For the three coplanar vector a→,b→ and c→ , their scalar tripe product a→.(b→×c→) must be zero.Here a→.(b→×c→)=|ax ay azbx by bzcx cy cz|=| 2 −1 1 1 2 −3 3 p 5 |=2(10+3p)+1(5+9)+1(p−6)⇒28+7p=0Or p=−4