First slide

Diodes

Question

The value of current in the following diagram will be

Easy

A

zero
B

$10^{- 2} A$
C

$10 A$
D

$0.025 A$

Solution

$D i o d e i s c o n n e c t e d i n f o r w a r d b i a \sin g a n d h e n c e b e h a v e s l i k e c o n d u c t i n g w i r e . A p p l y O h m' s L a w :$
$I = \frac{V}{R} = \frac{(5 - 3)}{200} = 10^{- 2} A$

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