First slide

Phasors and Phasor Diagrams

Question

The value of the current through an inductance of 1 H and of negligible resistance, when connected through an AC source of 200 V and 50 Hz, is

Easy

A

0.637 A
B

1.637 A
C

2.637 A
D

3.637 A

Solution

$i = \frac{V}{X_{L}} = \frac{200}{ωL} = \frac{200}{2 π \times 50 \times 1} = 0 .637 A$

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