First slide

Acceleration due to gravity and its variation

Question

The value of g (acceleration due to gravity) at earth's surface is 10 ms^-2. Its value in ms^-2 at the centre of the earth which is assumed to be a sphere of radius R metre and uniform mass density is

Moderate

A

5
B

$\frac{10}{R}$
C

$\frac{10}{2 R}$
D

zero

Solution

Inside the earth $g^{'} = g [1 - \frac{h}{R}]$
At centre $g^{'} = g [1 - \frac{R}{R}] = 0$

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