The value of g at a particular point is 10 ms-2. Suppose the earth shrinks uniformly to half of its present size without losing any mass. The value of g at the same point (assuming that the distance of the point from the centre of the earth does not change) will now be
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a
5ms−2
b
10ms−2
c
3ms−2
d
20ms−2
answer is B.
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Detailed Solution
F=(GMm)/R2=mgAs the mass remains the same and radius, i.e., distance from the centre is also the same, therefore g will remain the same, i.e., 10 m s-2.