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The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is 

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a
1×102N/m
b
150 N/m
c
0.667×102N/m
d
3×102N/m

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detailed solution

Correct option is B

Total potential energy = 0.04 JResting potential energy =0.01 JMaximum kinetic energy =(0.04–0.01)=0.03J=12m ω2a2=12ka20.03=12×k×2010002k=0.06×2500 N/m=150 N/m


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