The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1×102N/m
b
150N/m
c
0.667×102N/m
d
3×102N/m
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Total potential energy = 0.04 JResting potential energy =0.01 JMaximum kinetic energy =(0.04 - 0.01) = 0.03 J0.03J=12mω2a2=12ka20.03=12×k×2010002k=0.06×2500N/m=150N/m