The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is _______

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1 × 102 N/m

1.5 × 102 N/m

2 × 102 N/m

3 × 102 N/m

answer is B.

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Detailed Solution

Energy of oscillation = (0.04 – 0.01)J = 0.03 J.∴ 12.k. 20 × 10−32=0.03.⇒ k=1.5 × 102 N/m

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