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Q.

The variation of velocity of a particle moving along a straight line is shown in figure. The distance travelled by the particle in 12 s is

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a

37.5 m

b

32.5 m

c

35.0 m

d

None of these

answer is A.

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Detailed Solution

Area from 0 to 10s=12[10+4]5=35 Area from 10 to 12s=12×2×(−2.5)=−2.5m Distance travelled =35+2.5=37.5m
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