First slide

Graphical representation-Motion in 1 d

Question

The variation of velocity of a particle moving along a straight line is shown in figure. The distance travelled by the particle in 12 s is

Moderate

A

37.5 m
B

32.5 m
C

35.0 m
D

None of these

Solution

$\begin{array}{l} Area from 0 to 10 s = \frac{1}{2} [10 + 4] 5 = 35 \\ Area from 10 to 12 s = \frac{1}{2} \times 2 \times (- 2.5) = - 2.5 m \\ Distance travelled = 35 + 2.5 = 37.5 m \end{array}$

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