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A varying horizontal force F=at acts on a block of mass m  kept on a smooth horizontal surface. An identical block is kept on the first block. The coefficient of friction between the blocks is μ .The time after which relative sliding between the blocks prevails is 

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a
2mga
b
2μmga
c
μmga
d
2μmga

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detailed solution

Correct option is B

GivenHorizontal force F=at Coefficient of friction =μ For upper block : fs=ma​For lower block : F−fs=ma​Solving we get,​fs=F2​Relative sliding starts when fs cross the value fL.​∴fs=fL​⇒F2=μmg​⇒at2=μmg​⇒t=2μmga


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(Take  g=10ms2)


 


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