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Questions  

Vector P=6i^+42j^+42k^ makes an angle with Z-axis which is equal to

a
cos-125
b
cos-122
c
cos-1225
d
None of these

detailed solution

Correct option is C

P=6i^+42j^+42k^Let P makes angle γ with Z - axis.∴  γ=cos-1PzPHere, Pz = 42and P=(6)2+(42)2+(42)2=10∴  γ=cos-14210=cos-1225

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