A vector P=3i^-2j^+ak^ is perpendicular to the vector Q=2i^+j^-k^. The value of a is
2
1
4
3
Since, vector P is perpendicular to the vector Q.
∴ P·Q=0⇒(3i^-2j^+ak^)·(2i^+j^-k^)=0
⇒ 6-2-a=0⇒a=4