Q.

The vectors a→ and b→ are such that |a→+b→|=|a→−b→|, then the angle between a→ and b→ will be

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a

π3

b

π

c

π2

d

Zero

answer is C.

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Detailed Solution

(a→+b→).(a→+b→)=(a→−b→).(a→−b→) Or a2+b2+2a→.b→=a2+b2−2a→.b→Or 4a→.b→=0  a→.b→=0Or abcosθ=0  ∴θ=900
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The vectors a→ and b→ are such that |a→+b→|=|a→−b→|, then the angle between a→ and b→ will be