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A vehicle of mass m is moving on a rough horizontal road with momentum p, If the coefficient of friction between the tyres and the rod be $μ$ , then stopping distance is

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p2μmg

p2μm2g

p22μmg

p22μm2g

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detailed solution

Correct option is D

Let x be the stopping distance. Then using the equation v2=u2+2ax, we have v2=0+2(F/m)x (where F/m=a, retardation) ∴ x=12mv2F=p2/2mμmg=p22μm2g

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