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Q.

The velocities of two particles A and B of same mass are VA→ = ai⏞   and VB→ = bj⏞ where a and b are constants. The acceleration of particle A is (2ai⏞+4bj⏞) and acceleration of particle B is (ai⏞-bj⏞)(in m/s2). The centre of mass of two particle will move in:

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a

straight line

b

parabola

c

ellipse

d

circle

answer is A.

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Detailed Solution

Vcom→ = m1V1→+m2V2→ m1+m2 = V→1+V→22 = ai⏞+bj⏞2acom→ = a1+a22 = 32(ai⏞+bj⏜)V→com is parallel to a→com. Hence path will be straight line.
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