The velocity, acceleration and force in two systems of units are related as under: (i) v′=α2βv (ii) a′=(αβ)a (iii) F′=1αβFAll the primed symbols belong to one system and unprinted ones belong to the other system. α and β arc dimensionless constants. Which of the following is/are correct?
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a
Length standards of the systems are related by: L′=α3β3L
b
Mass standards of the two systems are related by: M′=1α2β2M
c
Time standards of the two systems are related by: T′=αβ2T
d
Momentum standards of the systems are related by: P′=1β3P
answer is A.
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Detailed Solution
Velocity = length/time, acceleration = length/(time)2⇒ Length =( velocity )2 acceleration i.e., L′=v′2a′,L=v2a⇒ L′L=v′v2aa′=α2β21αβ=α3/β3Now, m′=F′a′,m=Fam′m=F′Faa′=1αβ×1αβ=1α2β2Time = velocity / acceleration, i.e.,T′=v′a′ and T=vaT′T=v′vaa′=α2β1αβ=αβ2Momentum = mass x velocityp′=m′v′,P=mv,p′p=m′mv′v=1α2β2α2βα2β=1β3