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The velocity of air over the upper surface of the wing of aeroplane is 20m/s and that on the lower surface is 10m/s. If the area of the wing is 10m2 and the mass of the wing is 400kg the net force acting on the wing is (Density of air =2kg/m3 and g=10m/s2 )

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a

1000 N down ward

b

500 N down ward

c

1000 N up ward

d

500 N upward

answer is A.

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Detailed Solution

Weight =mg = 400×10=4000N Up thrust =ρ2A(v22−v12)=22×10((20)2−(10)2) =10×(400−100) =10×300=3000N Net force =4000 – 3000 N = 1000N (down)

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The velocity of air over the upper surface of the wing of aeroplane is 20m/s and that on the lower surface is 10m/s. If the area of the wing is 10m2 and the mass of the wing is 400kg the net force acting on the wing is (Density of air =2kg/m3 and g=10m/s2 )