Velocity of the body on reaching the ground is same in magnitude in the following casesa) a body projected vertically from the top of tower of height 'h' with velocity 'u'b) a body thrown down wards with velocity 'u' from the top of tower of height 'h'c) a body projected horizontally with a velocity 'u' from the top of tower height 'h'd) a body dropped from the top tower of height 'h'

For the body projected vertically upwards we can write ,V2 = (-u)2 + 2gh = u2 +2ghFor the body projected vertically downwards we can write ,V2 = u2 +2ghFor the body projected horizontally with velocity 'u' , horizontal component of velocity just before it strikes the groud is Vh = uAnd vertical component of velocity just before it strikes the ground isVv2 = 0 + 2gh.: If 'v' be the speed of the projectile just before it strikes the ground is given by ,V2 = Vh2 +Vv2 = u2 + 2ghFor the body dropped from the top of a tower of height h , its speed v just before it strikes the ground is given byV2 = 0 +2ghSo ,option (2) is correct.