The velocity of the body that travels a distance of (13.8±0.2) m unimormally in a time (4.0±0.3)s is

Here, the distance is given asS=(13.8±0.2)mAnd time taken as t=(4.0±0.3)secExpressing it in percentage error, we haveS=13.8±0.213.8×100%=13.8+1.4% andt=4.0±0.34×100%=4±7.5%Now velocity is given as V=St. So,% error in V=% error in S+% error in V = 8.9%In error form,V=13.8+0.24.0±0.3=3.45±8.9%=3.45±8.9100×3.45=(3.45±0.3)ms−1