The velocity- displacement graph of a particle is shown in the figure.The acceleration – displacement graph of the same particle is represented by:
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a
b
c
d
answer is B.
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Detailed Solution
From the graph V=−V0X0x+V0Differentiating w.r.t, time a=dVdt=−V0x0dxdt=−V0x0V ⇒a=−V0x0−V0x0x+V0⇒a=V0x02x−V02x0 So, the graph is a straight line with positive slope and negative intercept .