The velocity of a freely falling body changes as gphq where g is acceleration due to gravity and h is the height. The values of p and q are

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1,12

12,12

12,1

1, 1

answer is B.

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Detailed Solution

v∝gphq (given)By substituting the dimension of each quantity and comparing the powers in both sides we get LT−1=LT−2p[L]q⇒p+q=1,−2p=−1∴p=12,q=12

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