Velocity is given by v = 4t (1 - 2t), then find the value of time at which velocity is maximum.

To find value of time at which velocity is maximum, taking differentiation of v with respect to time                        dvdt=0Given,              v = 4t (1 - 2t)                         v=4t-8t2⇒ddt4t-8t2=0 ⇒        4-16t=0   ⇒  t=14 s=0.25 sAgain, taking differentiation, we get⇒          d2vdt2=-16<0So, at t = 0.25 s, velocity is maximum.