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The velocity at the maximum height of a projectile is half of its initial velocity of projection (μ). Its range
on horizontal plane is

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a
3μ2g
b
μ2g
c
μ23g
d
32μ2g

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detailed solution

Correct option is D

Given,  ucosθ=u2⇒θ=60°Now,  R=u2sin2θg=u2sin120°g=3u22g


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