The velocity at the maximum height of a projectile is half of its initial velocity of projection (μ). Its rangeon horizontal plane is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

3μ2g

μ2g

μ23g

32μ2g

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given, ucosθ=u2⇒θ=60°Now, R=u2sin2θg=u2sin120°g=3u22g

Watch 3-min video & get full concept clarity