First slide

Projection Under uniform Acceleration

Question

The velocity at the maximum height of a projectile is half of its initial velocity of projection. The angle of projection is

Moderate

A

30⁰
B

45⁰
C

60⁰
D

76⁰

Solution

$\large u\cos \theta = \frac{1}{2}u \Rightarrow \cos \theta = \frac{1}{2} = \cos {60^0} \Rightarrow \theta = {60^0}$

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