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The velocity at the mean position of the bob of a pendulum is SHM is v. If its  amplitude is doubled keeping the length the same, its velocity in the mean position  will be 

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a
v
b
2v
c
3v
d
4v

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detailed solution

Correct option is B

v=Aω⇒v1=(2A)=2v


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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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