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Q.

The velocity of a moving particle varies with distance moved as v=(4+3x) ms−1. If mass of the particle is 1kg, then the work done on the particle during the time its displacement changes from x=1m to x=2m is______

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answer is 25.5 J.

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Detailed Solution

v=4+3x a=vdvdx=(4+3x)×3a=3[4+3x]W=∫ma⁡dx=∫12 1×3(4+3x)dxW=34[x]12+3x2212=24×(2−1)+32(4−1)W=34+32×3=3[4+4.5]=3×8.5W=25.5J

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