Questions
Velocity of a particle of mass I kg moving rectilinearly is given by , v = 25- 2t + t2. Find the average power of the force acting on the particle between time interval t = 0 to t = 1 sec.
detailed solution
Correct option is D
Average power, Pav=ΔKEΔt=12mv2−u2ΔtHere, u = 24 m/s, u = 25 m/s, ∆t = 1sTherefore, Pav=12×1242−252W=−24.5WTalk to our academic expert!
Similar Questions
The heart of a man pumps 5 litres of blood through the arteries per minute at a pressure of 150 mm of mercury. If the density of mercury be then the power of heart in watt is:
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
