Velocity of a particle of mass 2 kg changes from v1→=−2i^−2j^ m/s to v2→=i^−j^ m/s after colliding with a smooth plane surface.
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a
The angle made by the plane surface with the positive x-axis is 90º + tan−113
b
The angle made by the plane surface with the positive x-axis is tan−113
c
The direction of change in momentum makes an angle tan−113 with the positive x-axis
d
The direction of change in momentum makes an angle 90º +tan−113 with the plane surface.
answer is A.
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Detailed Solution
ΔP→=2(i^−j^)−2(−2i^−2j^)=6i^+2j^km/sSo, ΔP→ makes angle tan−113 with positive x-axis which is also the direction of normal force exerted on the ball. So the plane surface makes an angle π2+tan−113 with positive x-axis.