First slide
Second law
Question

Velocity of a particle of mass 2 kg varies with time 't' according to the equation v=(2ti^4j^)m/s m/s. Here 'r' is in seconds. The impulse imparted to the particle in the time interval 0 ≤ t ≤ 2s is:

Moderate
Solution

Impulse = Change in momentum
=2[(2×2i^4j^)(2×0i^4j^)]=(8i^)kgm/s

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