Velocity of a particle of mass $$2$$ kg varies with time 't' according to the equation v→$$=(2ti^$$−$$4j^)m/s$$ $$m/s$$. Here 'r' is in seconds. The impulse imparted to the particle in the time interval $$0$$ ≤ t ≤ $$2s$$ is:

Correct option is 4(8i^)kg−m/s

Questions

Velocity of a particle of mass 2 kg varies with time 't' according to the equation $\vec{v} = (2 t \hat{i} - 4 \hat{j}) m / s$ m/s. Here 'r' is in seconds. The impulse imparted to the particle in the time interval 0 ≤ t ≤ 2s is:

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(4i^)kg−m/s

(8i^−4j^)kg−m/s

(8i^+4j^)kg−m/s

(8i^)kg−m/s

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detailed solution

Correct option is D

Impulse = Change in momentum=2[(2×2i^−4j^)−(2×0i^−4j^)]=(8i^)kg−m/s

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Velocity of a particle of mass 2 kg varies with time 't' according to the equation v→=(2ti^−4j^)m/s m/s. Here 'r' is in seconds. The impulse imparted to the particle in the time interval 0 ≤ t ≤ 2s is:

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Ready to Test Your Skills?

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Velocity of a particle of mass 2 kg varies with time 't' according to the equation $\vec{v} = (2 t \hat{i} - 4 \hat{j}) m / s$ m/s. Here 'r' is in seconds. The impulse imparted to the particle in the time interval 0 ≤ t ≤ 2s is: