Velocity of a particle moving along positive $$x-direction$$ is $$v=(40-10$$ $$t)$$. Here, t is in seconds At time $$t=0$$, the $$x-coordinate$$ of particle is zero. Find the time when the particle is at a point $$(-60$$ m,$$0)$$ from origin.

Question

Velocity of a particle moving along positive $$x-direction$$ is $$v=(40-10$$ $$t)$$. Here, t is in seconds At time $$t=0$$, the $$x-coordinate$$ of particle is zero. Find the time when the particle is at a point   $$(-60$$ m,$$0)$$ from origin.

Infinity Learn · Accepted Answer

Comparing with $$v=u+at$$, we have $$u=40$$ $$m/s$$ and $$a=-10$$ $$m/s2Distance$$ of $$60$$ m from origin may be at $$x=+60$$ m and $$x=-60$$ m.From the figure, we can see that at these two points particle is at three times, $$t1$$, $$t2$$ and $$t3$$.For $$X=+60$$ m $$ort1$$ and $$t2s=ut+12at2$$ ⇒  $$60=(+40)t+12(-10)t2Solving$$ this equation, we $$gett1=2$$ s and $$t2=6$$ sFor $$X=-60$$ mor $$t1s=ui+12at2$$ $$-60=(+40)t+12(-10)t2Solving$$ this equation, we get positive value of t is $$t3=2(2+7)s$$

Velocity of a particle moving along positive $x$ -direction is $v = (40 - 10 t)$ . Here, $t$ is in seconds At time $t = 0$ , the $x$ -coordinate of particle is zero. Find the time when the particle is at a point $(- 60 m, 0)$ from origin.

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Velocity of a particle moving along positive x-direction is v=(40-10 t). Here, t is in seconds At time t=0, the x-coordinate of particle is zero. Find the time when the particle is at a point (-60 m,0) from origin.

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Velocity of a particle moving along positive $x$ -direction is $v = (40 - 10 t)$ . Here, $t$ is in seconds At time $t = 0$ , the $x$ -coordinate of particle is zero. Find the time when the particle is at a point $(- 60 m, 0)$ from origin.