The velocity of particle undergoing SHM at the mean position is $$4m/s$$. Find the velocity of the particle at the point where the displacement from the mean position is equal to half the amplitude

Question

Infinity Learn · Accepted Answer

given velocity at mean position,which is maximum velocity as $$Vmax=4m/sVelocity$$ of simple harmonic oscillator is $$V=$$ω$$A2-x2$$ ⇒at $$x=0$$ , mean position, $$Vmax=$$ωA given ω$$A=4m/s$$              $$V=$$ω$$A2-x2$$           at $$x=A2$$, $$velocity=$$ω$$A2-A2/4=$$ω$$3A2/4$$              $$V=$$ω$$A32$$, substitute ω$$A=4$$,               $$V=432=23m/s$$

The velocity of particle undergoing SHM at the mean position is 4m/s. Find the velocity of the particle at the point where the displacement from the mean position is equal to half the amplitude

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