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The velocity' of a particle is $v ∣ = 6 \hat{i} + 2 \hat{j} - 2 \hat{k}$ . The component of the velocity parallel to vector $a = \hat{i} + \hat{j} + \hat{k}$ in vector form is

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6i^+2j^+2k^

2i^+2j^+2k^

i^+j^+k^

6i^+2j^-2k^

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detailed solution

Correct option is B

Magnitude of component of v along a=v·aa=6+2-23=23Now, a^=i^+j^+k^3∴ Component of velocity in vector form =23a^=(2i^+2j^+2k^)

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The velocity' of a particle is v∣=6i^+2j^-2k^. The component of the velocity parallel to vector a=i^+j^+k^ in vector form is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The velocity' of a particle is $v ∣ = 6 \hat{i} + 2 \hat{j} - 2 \hat{k}$ . The component of the velocity parallel to vector $a = \hat{i} + \hat{j} + \hat{k}$ in vector form is