The velocity of a particle V=U+mt+nt2 its position is x=0 at t=0. Then its displacement after a unit time
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a
U+m2+n
b
U+2m+3n
c
U+m2+n3
d
U+m+n
answer is C.
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Detailed Solution
at t=0,x=0V=U+mt+nt2differential form of velocity=dxdt, substitute in above equationdxdt=U+mt+nt2⇒dx=U+mt+nt2dtintegrating to get displacement,⇒∫0x dx=∫0t Udt+∫0t mtdt+∫0t nt2dt ⇒x=Ut+mt22+nt33 In unit time , substitute t=1sec The displacement S=U+m2+n3