First slide

Position Path Length (Distance) And Displacement

Question

The velocity of a particle is v : v₀ + gt + ft² .If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is:

Moderate

A

$v_{o} + \frac{g}{2} + f$
B

v₀+2g+3f
C

$v_{o} + \frac{g}{2} + \frac{f}{3}$
D

V₀+g+f

Solution

$∵ v = \frac{dx}{dt} ∴ \int dx = \int v dt$
$\Rightarrow Δx = \int_{0}^{1} (v_{o} + gt + {ft}^{2}) dt$
$= {(v_{o} t + g \frac{t^{2}}{2} + f \frac{t^{3}}{3})}_{0}^{1}$
$= v_{o} + \frac{g}{2} + \frac{f}{3}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App